Thread "Extreme Math Challenge... Squared!" in forum "MAFIA... and other forum games"

Posted at 2:03AM, Mar. 14, 2008

TODAY'S PI DAY!!!

In honor of today, I will post math problems! If someone dares to answer a problem and answers correctly, I will post an even more difficult problem.

Your rewards through this process:
- new mathematical knowledge
- a newfound appreciation of math
- miscellaneous unknown things

FUN! FUN! FUN! GO!

Q1:
Solve.

1+1

Posted at 12:03PM, Mar. 14, 2008

An extreme math challenge, eh? How edumacational! Okay, I'll solve this one:

1+1=2

Ha! That was too easy (and I really suck at math)!

Posted at 1:03PM, Mar. 14, 2008

Hard mode guys.

4x - 1 = 7

WHAT IS X?

Posted at 2:03PM, Mar. 14, 2008

4x - 1 = 7
4x = 8 by the Subtraction Property of Equality
x = 2 by the Division Property of Equality

Therefore x = 2

:D!

Posted at 3:03PM, Mar. 14, 2008

Increase difficulty!

Solve for x:

|2x-4| = 12

Posted at 6:03PM, Mar. 14, 2008

2x-4 = 12
2x = 16
x = 8

2x-4 = -12
2x = -8
x = -4

sooo…
x equals -4 or 8.

:D!

Posted at 12:03PM, Mar. 15, 2008

Increase difficulty!

Solve for x:

x^2 + 24 = 10x

Posted at 2:03PM, Mar. 15, 2008

x^2 + 24 = 10x

x^2 -10x + 24 = 0

(x-6)(x-4) = 0

x = 6 or 4

Increase difficulty!

In a right angle triangle, the two shorter sides are 3 and 4 inches. What is the length of the longest side?

Posted at 4:03PM, Mar. 15, 2008

Since it's a Pythagorean triple, 5!

:3

Posted at 6:03PM, Mar. 15, 2008

Increase difficulty!

What is the sum of the coefficients in this expre20ssion:

20x^3 + 3x^2 - 7x + 13

Posted at 3:03PM, Mar. 16, 2008

The coefficients of
20x^3 + 3x^2 - 7x + 13
are 20, 3, -7 and 13.

Therefore the sum is 20 + 3 + (-7) + 13 = 29.

Increase difficulty!

Evaluate d/dx(x^2 + 2x + 4)

Posted at 10:03AM, Mar. 17, 2008

Decrease Dificulty

3x4+56-1223+10000=

Posted at 8:03PM, Mar. 17, 2008

Baconator's answer:
2x + 2

cool guy's answer:
8845

Increase difficulty!

Solve y(t) in terms of t:

y'(t) - y(t) = 0

Posted at 10:03PM, Mar. 18, 2008

I'm not quite sure about that one, but the way I see it…

y'(t) - y(t) = 0
y'(t) = y(t)

And for the derivative of a function y to be exactly equal to that function y, the only thing I could think is that..

y(t) = e^t
since d/dt(e^t) = e^t

But I'm not sure that I can exactly assume that…nor am I sure if that's the kind of thing you're looking for.

—————————–

Decrease difficulty!

If vectors u = (2x, 3(y^2), 1/z) and v = (1/x, -(y^-2), z), then what is the dot product of u and v?

Posted at 8:03PM, Mar. 21, 2008

WTF?

…

Shoop Da Hoop?

Posted at 3:03PM, Mar. 23, 2008

Hah I get where this is going.

ok Guys listen up!

1 + 1 =

1 = ln (e)
1 also = Sin^2(theta) + Cos^2(theta)

Where Cos^2 (theta) = (Cos2*(theta)+1)/2
Where Sin^2(theta) = (-Cos2*(theta)+1)/2

Thus giving you

ln(e) + ((Cos2*(theta)+1)/2 ) + ((-Cos2*(theta)+1)/2 ) = 1 + 1

Simple as Pi

Did I make a mistake?

Q2 was easy, like the guy up top said, e^y will do it :) since F' = F

Posted at 11:03PM, Mar. 23, 2008

To Baconator's last question:

Dot product equals 0.

*heh heh*
WARNING: EXTREME DIFFICULTY INCREASE!!!

Find the general solution of

y"(t) + y(t) = 2y'(t)

Posted at 8:03PM, Mar. 24, 2008

oh bugger, you said general… oh well, its a general ODE anyways, no forcing function. I don't wanna write it out…

Posted at 10:03PM, Mar. 27, 2008

The answer is y(t) = c1te^t + c2e^t in which c1 and c2 are distinct constants. Simple, is it not?

Reset difficulty.

Simplify: 2+2

Posted at 10:03PM, Mar. 28, 2008

4

Posted at 10:03AM, Mar. 29, 2008

INCREASE DIFFICULTY!

Solve:
6x9

Posted at 1:03PM, Mar. 29, 2008

6x9 = 54

—

INCREASE DIFFICULTY!

What is the slope of the line described by the following equation:

y^2 = 16(x^2)

Posted at 11:03AM, Mar. 30, 2008

Do you mean the gradient?

Posted at 6:03PM, Mar. 31, 2008

Nope.

Hint: the equation I gave is a line defined in 2-space…so compare it to the general equation of a line (y=mx + b)

It's a really simple question actually =P

Posted at 7:03PM, Mar. 31, 2008

Actually, it looks like a trick question since y^2 = 16(x^2) consists of two lines with slopes of 4 and -4 intersecting at the origin.